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219 points skadamat | 2 comments | | HN request time: 0s | source
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xnorswap ◴[] No.41301135[source]
My favourite corollary of this is that even if you win the lottery jackpot, then you win less than the average lottery winner.

Average Jackpot prize is JackpotPool/Average winners.

Average Jackpot prize given you win is JackpotPool/(1+Average winners).

The number of expected other winners on the date you win is the same as the average number of winners. Your winning ticket doesn't affect the average number of winners.

This is similar to the classroom paradox where there are more winners when the prize is poorly split, so the average observed jackpot prize is less than the average jackpot prize averaged over events.

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pif ◴[] No.41301213[source]
> The number of expected other winners on the date you win is the same as the average number of winners.

Sorry, but no! The total number of expected winners (including you) is the same as the average number of winners.

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xnorswap ◴[] No.41301245[source]
No, it's 1+average number of winners.

If the odds of winning are 1 in 14 million, and 28 million tickets are sold, then you expect there to be 2 winners.

If look at your ticket and see you've won the lottery, then the odds of winners are still 1 in 14 million, and out of the 27,999,999 other tickets sold, you expect 2 other winners, and now expect 3 winners total, given you have won.

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jncfhnb ◴[] No.41302412[source]
That doesn’t work very well when the average number of winners is much less than 1. The math might work out that the “expected value” is more than one winner but in a realistic lottery you should expect to be the only winner.
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1. TylerE ◴[] No.41302487{3}[source]
I'm not sure if this is true, as large jackpots see a higher than average number of tickets sold.
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2. jncfhnb ◴[] No.41302830[source]
It is true. The average power ball does not have a winner.