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200 points rbanffy | 3 comments | | HN request time: 0.881s | source
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lorenzohess ◴[] No.45655889[source]
Summary:

> Rather than allowing heat to build up, what if we could spread it out right from the start, inside the chip?... To do that, we’d have to introduce a highly thermally conductive material inside the IC, mere nanometers from the transistors, without messing up any of their very precise and sensitive properties. Enter an unexpected material—diamond.

> ... my research group at Stanford University has managed what seemed impossible. We can now grow a form of diamond suitable for spreading heat, directly atop semiconductor devices at low enough temperatures that even the most delicate interconnects inside advanced chips will survive... Our diamonds are a polycrystalline coating no more than a couple of micrometers thick.

> The potential benefits could be huge. In some of our earliest gallium-nitride radio-frequency transistors, the addition of diamond dropped the device temperature by more than 50 °C.

replies(1): >>45656776 #
kulahan ◴[] No.45656776[source]
Fifty Celsius is an insane drop.

It sounds like the most important part of the article (and another cool quote) is this:

>Until recently we knew how to grow it only at circuit-slagging temperatures in excess of 1,000 °C.

So basically, the big breakthrough was low-temp growth of a diamond lattice. Very cool they can do it at such a low temperature. It must be a crazy low temp - probably under 100C?

replies(2): >>45657044 #>>45657067 #
yorwba ◴[] No.45657067[source]
From the article:

"we were able to find a formula that produced coatings of large-grained polycrystalline diamond all around devices at 400 °C, which is a survivable temperature for CMOS circuits and other devices."

replies(2): >>45657194 #>>45659290 #
1. kulahan ◴[] No.45657194[source]
Thanks, not sure how I missed that. Still, a 60% drop in required temp! These gems are truly, truly outrageous.
replies(1): >>45658380 #
2. zeristor ◴[] No.45658380[source]
~50% it helps to do these calculations using the Kelvin scale.

Learnt that in Physics lab.

replies(1): >>45660688 #
3. kulahan ◴[] No.45660688[source]
That makes sense. A direct scale instead of degrees of representation. Thanks for the correction.