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856 points tontonius | 32 comments | | HN request time: 0.001s | source | bottom
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chrismorgan ◴[] No.45011025[source]
The “Better Gradients” thing is dodgy.

OKLCH is a polar coordinate space. Hue is angle in this space. So to interpolate hue from one angle to another, to get from one side of a circle to the other, you go round the edge. This leads to extreme examples like the one shown:

  linear-gradient(in oklch, #f0f, #0f0)
You can also go round the circle the other way, which will take you via blue–aqua instead of via red–yellow:

  linear-gradient(in oklch longer hue, #f0f, #0f0)
The gradient shown (in either case) is a good example of a way that perceptual colour spaces are really bad to work in: practically the entire way round the edge of the circle, it’s outside sRGB, in fact way outside of the colours humans can perceive. Perceptual colour spaces are really bad at handling the edges of gamuts, where slightly perturbing the values take you out of gamut.

Accordingly, there are algorithms defined (yes, plural: not every application has agreed on the technique to use) to drag the colour back in-gamut, but it sacrifices the perceptual uniformity. The red in that gradient is way darker than the rest of it.

When you’re looking for better gradients, if you’re caring about perceptual uniformity (which frequently you shouldn’t, perceptual colour spaces are being massively overapplied), you should probably default to interpolating in Oklab instead, which takes a straight line from one side of the circle to the other—yes, through grey, if necessary.

  linear-gradient(in oklab, #f0f, #0f0)
And in this case, that gets you about as decent a magenta-to-lime gradient as you can hope for, not going via red and yellow, and not exhibiting the inappropriate darkening of sRGB interpolation (… though if I were hand-tuning such a gradient, I’d actually go a bit darker than Oklab does).

During its beta period, Tailwind v4 tried shifting from sRGB to Oklch for gradient interpolation; by release, they’d decided Oklab was a safer default.

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djoldman ◴[] No.45012990[source]
But what really is a "color gradient"?

Isn't it any continuous function that starts at a specified color and ends at another specified color?

How then does one say that any gradient is good or bad?

Isn't the problem you are highlighting guaranteed to exist for any colorspace that defines colors outside of human perception?

replies(2): >>45013072 #>>45015813 #
1. layer8 ◴[] No.45013072[source]
A good gradient is one that takes a perceptually uniform, and typically perceptually shortest, path. The OKLCH gradient isn't perceptual uniform and appears to take unnecessary detours through other hues.
replies(1): >>45013444 #
2. cubefox ◴[] No.45013444[source]
One could also argue that the detour through other hues is necessary in this case to avoid going through grey.
replies(1): >>45013622 #
3. layer8 ◴[] No.45013622[source]
Gray is arguably just another color, it’s not clear why you’d want to avoid it. How is going via red and yellow better than going via gray? Varying hue is often perceived as a larger change than varying saturation or lightness. A path going through several distinct hues is visually less uniform than one going through gray once.
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4. the_af ◴[] No.45013704{3}[source]
Is gray perceived as "just another color" or where all colors go when desaturated? I assumed the latter, which would explain why to avoid it if one isn't playing with saturation.
replies(1): >>45014020 #
5. layer8 ◴[] No.45014020{4}[source]
Think of fashion, of smartphone colors, pen and pencil colors and the like. Gray, white, black, are just color choices among all the available colors. A gray T-shirt isn’t a desaturated colored T-shirt. It’s its own color.
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6. brulard ◴[] No.45014617{3}[source]
Let's say you continuously change wavelength of a laser from blue (~480nm) to red (~630nm), you are going through green, not through gray. If in your use case going through gray makes sense, that's ok, there may be many paths from one color to another.
replies(2): >>45015320 #>>45016520 #
7. the_af ◴[] No.45014920{5}[source]
Oh, I understand what you say. But in color spaces, isn't gray the "sink" towards which desaturated colors shift? This would make it a location to avoid (unless you're purposefully desaturating).
replies(1): >>45015668 #
8. cruffle_duffle ◴[] No.45014949{5}[source]
Color is weird like. Gray is “all the visible spectrum in equal proportions”, which is white… just less white than the whitest thing visible but more white than the darkest (blackest) thing visible.

It’s a “color” because it’s useful to describe such a thing. If you had monitor entirely filled with 50% white you’d call it white. Only by comparing it to something brighter do you call it gray. Brown is the same thing. In a dark room if you looked at a monitor filled with red and green pixels you’d call it orange. Only when you start adding in clues like whites and brighter colors would you call it brown.

Anyway, yes grey is a color. But it is not quite the same as other colors. Other colors occupy only parts of the visible electromagnetic spectrum. Whites are the whole thing.

There is actually several very good technology connections videos about this stuff. Color is very cool!

replies(1): >>45015707 #
9. AnimalMuppet ◴[] No.45015125{3}[source]
It depends on how you think about your spread. If, as someone else said, you're trying to represent a tunable laser going from red to blue, going through gray is completely wrong. That is not what a laser will do, ever. It will always be a fully saturated color.

So, depending on what you're doing, you want different things. You may want to view your color space as an RGB cube, and go through gray. Or you may want to view your color space as something more like HLS or OKLCH, and not go through gray.

10. Sharlin ◴[] No.45015320{4}[source]
In general people don't really think of color in terms of the spectral progression (or the hue wheel), and I don't think that most people intuitively expect a gradient between two colors to pass through another "unrelated" primary or secondary color. The point is somewhat moot though, given that such gradients (like yellow to blue or red to green) are very unnatural anyway.
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11. ◴[] No.45015668{6}[source]
12. seba_dos1 ◴[] No.45015707{6}[source]
> Whites are the whole thing.

...with varying definitions of "whole". D65 white is almost blue when compared to A white. It stops being either “all the visible spectrum" or "in equal proportions” pretty quickly once you look closer at it.

13. ghurtado ◴[] No.45016009{3}[source]
> Gray is arguably just another color

Only if you're working with additive color.

With substractive, grey is just a darker (or dimmer) white.

14. JKCalhoun ◴[] No.45016520{4}[source]
Shine a red and a green light near each other on a wall — what does the transition look like?
replies(1): >>45017085 #
15. ZoomZoomZoom ◴[] No.45017085{5}[source]
There's no transition, this is color mixing, or overlay in case of light.
replies(1): >>45017746 #
16. runarberg ◴[] No.45017636{5}[source]
Honestly I suspect this is largely a non issue. I have never made a gradient that goes through more than 2 different color (by some vague measure of different) without adding an additional stop. If I wanted to go through yellow and green to get to blue, I would add a stop at yellow and another at green, and I suspect most developers would do the same.
17. JKCalhoun ◴[] No.45017746{6}[source]
Is that not a transition through the color mixing (or overlay). I'm assuming the light sort of tails off as you leave the area of one color and head to the other (and the other color comes on with more intensity then).

I suppose that's different with light than some analog with pigments? (Two dabs of color set apart, a brush perhaps used to blend them as continuously as is possible.)

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18. gowld ◴[] No.45018017{5}[source]
It's funny and a bit sad because we just went througha decades-long effort to migrate away from jet/rainbow gradients to vik/batlow/bi-hue gradients, and now rainbow is forcing its way back.

https://theconversation.com/how-rainbow-colour-maps-can-dist...

https://www.poynter.org/archive/2013/why-rainbow-colors-aren...

19. itishappy ◴[] No.45018125{3}[source]
It's an ugly color. Saturation makes stuff pop; this is often desirable. This is why I think it's important to have both polar (OKLCH) and rectilinear (Oklab) gradients.
20. itishappy ◴[] No.45018195{5}[source]
I disagree somewhat. Color mixing just isn't particularly intuitive. It's not the most intuitive to get a third hue, but that doesn't justify grey (which has an undefined hue). I do think most people are quite comfortable with the fact that between blue and yellow exists green, but is it a saturated green or a desaturated green? Additive and subtractive color mixing behave very differently here.
21. itishappy ◴[] No.45018273{5}[source]
A grey shirt is a desaturated shirt. You cannot resaturate grey.

I think if you buy a tie-dye shirt or phone case and it comes out half grey, despite it being a valid color, most folks will be disappointed.

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22. cubefox ◴[] No.45018860{3}[source]
Let's say neither going through gray nor through two different hues looks particularly great. It's pick your poison.
23. Dylan16807 ◴[] No.45019549{6}[source]
> A grey shirt is a desaturated shirt. You cannot resaturate grey.

Aren't these in direct conflict? If you can't resaturate it, that implies it's not desaturated.

> I think if you buy a tie-dye shirt or phone case and it comes out half grey, despite it being a valid color, most folks will be disappointed.

And if you buy a forest motif, people will be upset if it's pink. That's just doing a tie-dye wrong, not a rebuke of whether it's a color at all.

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24. itishappy ◴[] No.45019869{7}[source]
> Aren't these in direct conflict? If you can't resaturate it, that implies it's not desaturated.

Kinda. There's a singularity in the math. The problem is that hue is defined as an angle and saturation is defined as distance from the center, but there's no consistent way to define a direction for the origin. Black and white have the same problem because they're also desaturated.

> And if you buy a forest motif, people will be upset if it's pink. That's just doing a tie-dye wrong, not a rebuke of whether it's a color at all.

I'm not arguing that it's not a color, just that it doesn't belong in all gradients!

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25. Dylan16807 ◴[] No.45019958{8}[source]
Of course it doesn't belong in all gradients. It would only be in gradients that go from near-opposite colors. Or if you mean pure gray it would only be in gradients between exact opposite colors, and there are no good options for such a gradient.
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26. itishappy ◴[] No.45020281{9}[source]
I mention tie-dye because it feels like a quintessential example of a color gradient. I think it's perfectly reasonable to ask for a blue and orange tie-dye shirt and perfectly reasonable to not want grey colors simply because they're on opposite sides. I could see white in between, I could even see black, or I could see purple and red or cyan and yellow. I don't think there's a universally right answer here!
replies(1): >>45020311 #
27. Dylan16807 ◴[] No.45020311{10}[source]
Someone asking for those colors doesn't actually want a gradient with two anchor points. So yes there are many answers but because it's not a quintessential example of a gradient.
replies(1): >>45020746 #
28. itishappy ◴[] No.45020746{11}[source]
> Someone asking for those colors doesn't actually want a gradient with two anchor points.

I thought the same until I googled "blue and orange tie-dye." I'll be honest, more white and black than I expected!

> So yes there are many answers but because it's not a quintessential example of a gradient.

We may have to agree to disagree that tie-dye isn't a quintessential example of a gradient. Would you argue that rainbows aren't either?

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29. cubefox ◴[] No.45020778{7}[source]
Your light thought experiment would produce a color gradient via additive color mixing.

A magenta to green gradient would then go through white rather than grey. A subtractive magenta-green gradient would go through black. Not sure what physical setup would produce the latter gradient. But the standard RGB (or OKLAB) gradient goes through grey rather than white or black. This type of gradient is physically created by dithering: Dithering a gradient from magenta to green, by just using these two base colors, would produce a perceptual grey in the middle. This type of color mixing is otherwise better known as alpha blending.

30. Dylan16807 ◴[] No.45021043{12}[source]
> I thought the same until I googled "blue and orange tie-dye." I'll be honest, more white and black than I expected!

Putting white or black in between adds another anchor point.

And looking more around examples of blue and orange tie dye, most aren't really gradients overall, they have big splotches of solid color with small gaps or overlaps in between, and at least half the time the gaps and overlaps don't even have a gradient inside them.

> We may have to agree to disagree that tie-dye isn't a quintessential example of a gradient. Would you argue that rainbows aren't either?

Hmm. How about this. I would say a rainbow is not a gradient between two colors, and the color space discussion is about a gradient between two colors. The exact border of "quintessential" is not something I really want to spend too much time on.

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31. itishappy ◴[] No.45021331{13}[source]
In my mind a gradient is simply a smooth transition between colors with no universally agreed upon definition. The choice of specific curve through colorspace is rather arbitrary. It seems perfectly reasonable to want to include grey and perfectly reasonable to want to avoid it.
32. DemocracyFTW2 ◴[] No.45024190{3}[source]
Gray is arguably not just another color; I don't know about English but in German you have 'bunte' and 'unbunte' colors; 'unbunte' colors are white, black, and the grays in between