Why 8 bit?
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Bedrock is a lightweight program runtime: programs assemble down to a few kilobytes of bytecode that can run on any computer, console, or handheld. The runtime is tiny, it can be implemented from scratch in a few hours, and the I/O devices for accessing the keyboard, screen, networking, etc. can be added on as needed.
I designed Bedrock to make it easier to maintain programs as a solo developer. It's deeply inspired by Uxn and PICO-8, but it makes significant departures from Uxn to provide more capabilities to programs and to be easier to implement.
Let me know if you try it out or have any questions.
In what sense does a virtual machine instruction set architecture with no hardware implementation have a "data path" separate from its arithmetic size? You seem to be using the term in a nonstandard way, which is fine, but I cannot guess what it is.
By your other criteria, the (uncontroversially "16-bit") 8088 would be an 8-bit computer, except that it had a 20-bit address space.
For example, the spec says, "Reading a double from program memory will read the high byte of the double from the given address and the low byte from the following address," but I'd think that generally you'd want the implementation to work by reading the whole 16-bit word at once and then byte-swapping it if necessary, because that would usually be faster, and there's no way for the program to tell if it's doing that, unless reading from the first byte has a side effect that changes the contents of the second byte or otherwise depends on whether you were reading the second byte at the same time.
(Of course if you have a "double" that crosses the boundaries of your memory subsystem's word, you have to fall back to two successive word reads, but that happens transparently on amd64 CPUs.)