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548 points nsagent | 1 comments | | HN request time: 0.432s | source
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lukev ◴[] No.44567263[source]
So to make sure I understand, this would mean:

1. Programs built against MLX -> Can take advantage of CUDA-enabled chips

but not:

2. CUDA programs -> Can now run on Apple Silicon.

Because the #2 would be a copyright violation (specifically with respect to NVidia's famous moat).

Is this correct?

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saagarjha ◴[] No.44567309[source]
No, it's because doing 2 would be substantially harder.
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lukev ◴[] No.44567356[source]
There's a massive financial incentive (billions) to allow existing CUDA code to run on non-NVidia hardware. Not saying it's easy, but is implementation difficulty really the blocker?
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1. int_19h ◴[] No.44573767[source]
From the market perspective, it's down to whether the amount of money needed to get there and stay there (keeping in mind that this would have to be an ongoing effort given that CUDA is not a static target) is more or less than the amount of money needed to just buy NVIDIA GPUs.