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269 points OlympicMarmoto | 1 comments | | HN request time: 0s | source

I discovered this collision detection algorithm during COVID and finally got around to writing about it.

github repo: https://github.com/cairnc/sat_blog

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msteffen ◴[] No.44512706[source]
I'm trying to work through the math here, and I don't understand why these two propositions are equivalent:

1) min_{x,y} |x-y|^2

   x ∈ A

   y ∈ B
2) = min_{x,y} d

   d ≥ |x-y|^2

   x ∈ A

   y ∈ B
What is 'd'? If d is much greater than |x-y|^2 at the actual (x, y) with minimal distance, and equal to |x-y|^2 at some other (x', y'), couldn't (2) yield a different, wrong solution? Is it implied that 'd' is a measure or something, such that it's somehow constrained or bounded to prevent this?
replies(4): >>44512964 #>>44513600 #>>44514056 #>>44515013 #
1. Jaxan ◴[] No.44513600[source]
But why would d be much greater. The problem asks to minimise d, and so it cannot be greater than the smallest |x-y|^2.