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A leap year check in three instructions

(hueffner.de)
434 points gnabgib | 3 comments | 15 May 25 21:57 UTC | HN request time: 0.43s | source
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captaincrunch ◴[15 May 25 22:46 UTC] No.44000123[source]▶
This is fast, READABLE, and accurate:

bool is_leap_year(uint32_t y) { // Works for Gregorian years in range [0, 65535] return ((!(y & 3)) && ((y % 25 != 0) || !(y & 15))); }

replies(3): >>44000304 #>>44000522 #>>44003153 #
kragen ◴[15 May 25 23:57 UTC] No.44000522[source]▶
You commented out your entire function body and the closing }. Also, on 32-bit platforms, it doesn't stop working at 65535.
replies(1): >>44001008 #
1. captaincrunch ◴[16 May 25 01:26 UTC] No.44001008[source]▶
just a formatting issue on my side, there were \n.
replies(2): >>44003548 #>>44007925 #
2. archargelod ◴[16 May 25 10:01 UTC] No.44003548[source]▶
This website eats newlines, unless you double them (one of the annoying features of markdown). You can use codeblocks by putting 4 spaces before each line:

    int main() {
        // this should be properly formatted
        return 0;
    };
3. kragen ◴[16 May 25 17:28 UTC] No.44007925[source]▶
If you fix it, other people can test your code without having to fix the syntax themselves first.