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pizlonator ◴[] No.42476714[source]
Compiling a tiny subset of C, that is. It might be so tiny as to be useless in practice.

I have low hopes for this kind of approach; it’s sure to hit the limits of what’s possible with static analysis of C code. Also, choosing Rust as the target makes the problem unnecessarily hard because Rust’s ownership model is so foreign to how real C programs work.

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pornel ◴[] No.42476961[source]
Rust's ownership model is close enough for translating C. It's just more explicit and strongly typed, so the translation needs to figure out what a more free-form C code is trying to do, and map that to Rust's idioms.

For example, C's buffers obviously have lengths, but in C the length isn't explicitly tied to a pointer, so the translator has to deduce how the C program tracks the length to convert that into a slice. It's non-trivial even if the length is an explicit variable, and even trickier if it's calculated or changes representations (e.g. sometimes used in the form of one-past-the-end pointer).

Other C patterns like `bool should_free_this_pointer` can be translated to Rust's enum of `Owned`/`Borrowed`, but again it requires deducing which allocation is tied to which boolean, and what's the true safe scope of the borrowed variant.

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pizlonator ◴[] No.42477145[source]
Rust’s ownership model forbids things like doubly linked lists, which C programs use a lot.

That’s just one example of how C code is nowhere near meeting Rust’s requirements. There are lots of others.

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orf ◴[] No.42477256[source]
> Rust’s ownership model forbids things like doubly linked lists, which C programs use a lot.

It’s literally in the standard library

https://doc.rust-lang.org/std/collections/struct.LinkedList....

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1. ◴[] No.42477296[source]