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A bestiary of exotic hadrons

(cerncourier.com)
152 points rbanffy | 1 comments | 20 Dec 24 15:29 UTC | HN request time: 0.208s | source
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addaon ◴[20 Dec 24 16:33 UTC] No.42472499[source]▶
"also implies the existence of a Tbb state, with a bbud quark content, that should be stable except with regard to weak decays"

Can someone explain this to me?

Tcc(3875)+ can decay to a D0 and a D+, yes? And this is a strong decay?

I guess the reason Tbb doesn't have an equivalent strong decay to B mesons because of the sign difference -- that is, B0 and B+ would have anti-bs, not bs; and anti-B0 and anti-B+ would have negative charge?

And so the only major decay pathway is for the b itself to decay to a K+ (plus lepton noise), giving a temporary bu\s\u\d pentaquark, that then has uninhibited decays?

I guess what I'm asking is... is this the right way to think about this?

replies(2): >>42472969 #>>42473030 #
1. dukwon ◴[20 Dec 24 17:32 UTC] No.42473030[source]▶
The strong decay would just be forbidden from conservation of energy. If the mass of the Tbb state is less than the sum of the B+ and the B0 masses, then that decay isn't allowed.