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104 points nomemory | 1 comments | | HN request time: 0.208s | source
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enugu ◴[] No.42186957[source]
One interesting result implies that numbers like 3^(sqrt(3)) will be transcendental (ie no polynomial will evaluate them to 0).

https://en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_theo...

replies(2): >>42187274 #>>42187305 #
wging ◴[] No.42187305[source]
Small but important correction: no polynomial with integer coefficients (equivalently, rational coefficients). p(x) = (x - 3^(sqrt(3))) is a perfectly fine polynomial with real coefficients.
replies(1): >>42191189 #
1. enugu ◴[] No.42191189[source]
Yes, I should have mentioned polynomials with rational coefficients(or indeed any algebraic numbers as coefficients due to transitivity of being algebraic).