While the benefit of processing chunks of 8 bytes is obvious, what's the purpose of grouping those into macrogroups of 4? Does it trigger any implicit parallelism I failed to spot? Or is it just to end this phase with the 4 h[] having had the same amount of entropy, and thus starting the next one with h[0]?
> The way it loads the 8 bytes is also important. The correct way is to load via shift+or > This is free of any UB, works on any alignment and on any machine regardless of it's endianness. It's also fast, gcc and clang recognize this pattern and optimize it into a single mov instruction on x86 targets.
Is a single MOV instruction still fast when the 8 bytes begin on an odd address?
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