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Industrious Dice

(mathenchant.wordpress.com)
136 points 082349872349872 | 5 comments | 17 Oct 24 17:32 UTC | HN request time: 0.875s | source
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cjg ◴[18 Oct 24 10:55 UTC] No.41878198[source]▶
Or a d6 with the 4, 5 and 6 faces blank. When you roll, if the face isn't blank, that's your number. If it is then flip the die over and subtract that number from 7.

Only uses 6 pips.

replies(1): >>41878766 #
1. ejddhbrbrrnrn ◴[18 Oct 24 12:26 UTC] No.41878766[source]▶
Pip position encoding can get that down to 3. One pip on 3 adjacent sides.

Centre pip = 1, Edge = 2, Corner = 3

replies(1): >>41878999 #
2. quirino ◴[18 Oct 24 12:56 UTC] No.41878999[source]▶
If we're gonna go that route, you can just put a single pip on a corner and derive all of the other positions from that.
replies(1): >>41879236 #
3. gcr ◴[18 Oct 24 13:24 UTC] No.41879236[source]▶
Nope, that’s rotationally symmetric around the (pip, center of dice) axis.

Put the pip on the face, but near the corner.

replies(2): >>41883594 #>>41889887 #
4. ejddhbrbrrnrn ◴[18 Oct 24 21:19 UTC] No.41883594{3}[source]▶
Or the edge so, the pipped face is 1, then go over that edge for 2, keep going around for 3 and 4. If we consider that "going east" then 5 is on the north pole.
5. quirino ◴[19 Oct 24 19:07 UTC] No.41889887{3}[source]▶
That's what I mean by "pip on the corner" :P

The comment above mine was using this terminology to refer to the corner of a face.