Such a waste of faces :). Give a tetrahedron's faces 0,1,2, and 4 pips and throw it into a v-shaped groove so that it lands on an edge. (This is also a solution to numbering the corners of a cube).
So you get, with equal probabilities, 0+1, 0+2, 1+2, 0+4, 1+4, or 2+4 = {1,2,3,4,5,6}. Same as 2:07 in the video, but using only 1/3 of the faces. Brilliant!