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1704 points ardit33 | 1 comments | | HN request time: 0s | source
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Findeton ◴[] No.24148096[source]
I don't think this should be regulated at all. Apple should be able to impose their rules in their systems. Let's be clear about this, if people are choosing to buy these black-box closed handheld computing devices, there are consequences that come with that choice.
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swiley ◴[] No.24148471[source]
Apple is more than welcome to put whatever rules they want on their systems. My phone is not their system though, it’s mine! If I want to run tmux/fetchmail/ocamlc on it then it’s my problem not theirs!
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rokobobo ◴[] No.24148851[source]
I am not defending closed platforms, but technically, you are free to jailbreak your phone, they're just not obligated to provide any support after that, right?

https://en.wikipedia.org/wiki/IOS_jailbreaking#Legality

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webstrand ◴[] No.24149214[source]
If Apple provided a way to jailbreak their devices, I'd be more inclined to support this argument. But they try to prevent jailbreaking at every opportunity so, regardless of the legality of it, Apple does not consider the phone your system, they consider it theirs.
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judge2020 ◴[] No.24149539[source]
No. There's no check for Cydia or other Debian Package frontends that are there to void your warranty or stop you from downloading cracked apps (they very well could do this). They only patch the security vulnerabilities that are actually used to break out of the app sandbox and run arbitrary code, something that, as we can see with Epic's Fortnite app, could be RCE'd into an app without Apple knowing. These vulnerabilities can and have been used by actual malware in the past[0], so Apple fixing them in iOS is a legitimate security measure.

0: https://blog.talosintelligence.com/2019/10/checkrain-click-f...

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1. ReverseCold ◴[] No.24149957{3}[source]
Right, but there’s no non-security-vulnerability way to jailbreak. If jailbreaking was as easy as `adb oem unlock`, no one would need to use any security issues to jailbreak.