What is it? The link points to a discussion more deep than I’m willing to read.
replies(10):
def foo():
if n := randint(0, 3):
return n ** 2
return 1337
[(x, y, x/y) for x in input_data if (y := f(x)) > 0]
if foo := bar[baz]:
bar[baz] += 1
return foo
else:
bar[baz] = 1
return 0
Where foo is a dict keeping track of multiple things, and a non-existing key (baz) is never an error but rather the start of a new count. Faster and more readable than if baz in list(bar.keys()):
....
Similar to Swift’s ‘if let’, it seems. m = re.match(r'\s*(\d+)\s*', args)
if m:
start = int(m.group(0))
end = start + 10
m = re.match(r'\s*(\d+)\s*,\s*(\d+)\s*', args)
if m:
start, end = map(int, m.groups())
With the new syntax this becomes: if m := re.match(r'\s*(\d+)\s*', args):
start = int(m.group(0))
end = start + 10
if m := re.match(r'\s*(\d+)\s*,\s*(\d+)\s*', args)
start, end = map(int, m.groups())
This pattern occurs just often enough to be a nuisance. For another example drawn from the standard library, here's modified code from "platform.py" # Parse the first line
if (m := _lsb_release_version.match(firstline)) is not None:
# LSB format: "distro release x.x (codename)"
return tuple(m.groups())
# Pre-LSB format: "distro x.x (codename)"
if (m := _release_version.match(firstline)) is not None:
return tuple(m.groups())
# Unknown format... take the first two words
if l := firstline.strip().split():
version = l[0]
if len(l) > 1:
id = l[1]